2^x(7/2)=28

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Solution for 2^x(7/2)=28 equation: 



2^x(7/2)=28

We move all terms to the left:

2^x(7/2)-(28)=0

We add all the numbers together, and all the variables

2^x(+7/2)-28=0

We multiply all the terms by the denominator


2^x(+7-28*2)=0

We add all the numbers together, and all the variables

2^x(-49)=0

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